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The below figure shows a Larson-Miller plot of three high temperature resistant alloys. On the basis of what is given on this graph, calculate the three rupture lifetimes at a stress level of 276 MPa and 880C. Select the best material based on creep resistance and briefly explain the difference in rupture times and the reason for your material selection. In your solution, please use the P (x-axis) values shown at the top of the graph (corresponding to temperature in Celsius) and ignore the P values shown at the bottom of the graph (corresponding to temperature in Fahrenheit). Stress (MPa) 22.2 690 552 414 276 207 138 69 Larsen-Miller parameter, P = [T(C) + 273] [20+ log(r)] 10- 23.3 24.4 25.5 26.7 27.8 28.9 30 31.1 DS MAR-M 247 longitudinal MFB, 1221C/2 h/GFO, 982C/5 h/AC. 871 C/20 h/AC, 1.8 mm diameter production data A Equiaxed MAR-M 247 MFB. 982 C/5 W/AC + 871C/20 h/AC and 871 C/20 h/AC only," 1.8 mm diameter specimens DS CM 247 LC, longitudinal, 1232C/2 h +1260C/20 h/AC 982C/5 h/AC, 871C/20 h/AC 3.2 and 4.1 mm diameter specimens B C DS CM 247 LC longitudinal, - 1232C/2h+ 1260C/2 W/AC.] 1079 C/4 h/AC, 871C/20 h/AC and 1232C/2h+1260C/20 h/AC. 1050C/16 h/AC, 871C/20 AC. 3.2 and 4.1 mm diameter specimens 40 46 48 50 52 54 Larsen-Miller parameter, P=[T(F) + 460] [20+ log(r)] 10-3 Figure 6.36 Larsen-Miller stress-rupture strength of directionally solidified (DS) CM LC alloy versus DS and equiaxed MAR-M 247 alloy. MFB: machined blade; GFQ: gas fan-quenched; AC: air-cooled. (After "Metals Handbook," vol. 1, 10th ed., ASM International, 1990, p. 998.)