Question: please dont solve below question ( solve Question 2) Question 1 Part A Determine the magnitude of the current through resistor R1, shown in the

 please dont solve below question ( solve Question 2)Question 1 PartA Determine the magnitude of the current through resistor R1, shown in

please dont solve below question ( solve Question 2)

Question 1

the figure below. The batteries have emfs of &, = 12.00 Vand &2 = 15.00 V and the resistors have values of R1= 11.8 0, R2 = 23.5 0, and R3 = 34.9 0.

Part A Determine the magnitude of the current through resistor R1, shown in the figure below. The batteries have emfs of &, = 12.00 V and &2 = 15.00 V and the resistors have values of R1 = 11.8 0, R2 = 23.5 0, and R3 = 34.9 0. R 3 MM &2- R 2 WW Submit Answer Tries 0/6 Part B Determine the magnitude of the current through resistor R2. Submit Answer|Tries 0/6 Part C Determine the magnitude of the current through resistor R3.34% of the heat released from burning fuel In a campstove actually goes to heating a pot and Its contents. You start with 1.1 kg of Ice at -9 IIC, 1.6 L of water at 16 C, and a 360 gram aluminum pot at 26 C. The Ice and water are put Into the pot and the system Is heated to 100 0C with 16% of the liquid boiling away. The specic heat of aluminum ls 0.22 cal/gC, The specic heat of ice is 0.5 cal/g-C. One gram of fuel produces 46000 J when It is burned, How much heat is required to go into the pot, water, and ice? (include units with answer) Format Check How much fuel needs to be burned? (include units with answer) Format Check How long would the total energy released by burning the fuel run a IOU-watt light bulb? (Use the Format Check C. amount of fuel from part B and _ _ OK - usmg rst assume all 46000J/gram goes to value as lighting the bulb) 0-000273 hr (include units with answer)

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