please explain how to work this problem

Given the second order initial value problem y" - 4y = 46(t - 5), y(0) = 4, y'(0) - -4 Let Y (s) denote the Laplace transform of y. Then Y(s) = Taking the inverse Laplace transform we obtain y ( t ) =Given the second order initial value problem y" - 4y = 46(t - 5), y(0) = -4, y'(0) = -4 Let Y (s) denote the Laplace transform of y. Then Y (s ) = (4(e^(-5s)-s-1))/(s^2-4) Taking the inverse Laplace transform we obtain y(t ) = -2(u(t-5)sinu(10-2t)+sinu(2t)+2cosu(2t))