Please need an answer asap

Use the Laplace transform to solve the following initial value problem: 3 - 4y' + 20y = 0 y(0) = 0, y (0) = 4 a. Using Y for the Laplace transform of y(t), i.e., Y = [fy(t)}, find the equation you get by taking the Laplace transform of the differential equation b. Now solve for Y(s) = C. By completing the square in the denominator and inverting the transform, find y(t) =. Note: You can Consider the initial value problem y" + 16y - 64t, y(0) - 4, y/(0) = 9. . Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y (s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). s =help (formulas) b. Solve your equation for Y(s). Y(s) = Cty(t)) = C. Take the inverse Laplace transform of both sides of the previous equation to solve for y(t). Use the Laplace transform to solve the following initial value problem: y' + 2y' = 0 y(0) = 1, y'(0) =4 a. Using Y for the Laplace transform of y(t), le.. Y = [fy(t)}, find the equation you get by taking the Laplace transform of the differential equation =0 b. Now solve for Y(s)= C. Write the above answer in its partial fraction decomposition, Y(s) = Tia + 75 where a