Please explain how you got your answer as I am struggling to understand how to solve this problem. Please note that the answer I put in was marked wrong

A summer camp offers a morning session and an afternoon session. The list morninglist contains the names of all children attending the morning ession, and the list afternoonlist contains the names of all children attending the afternoon session. Only children who attend both sessions eat lunch at the camp. The camp director wants to create a lunchlist, which will contain the names of children attending both sessions. The following code segment is intended to create lunchList, which is initially empty. It uses the procedure IsFound (list, name), which returns true it child is found in list and returns false otherwise. FOR EACH child IN morninglist { MISSING CODE } Which of the following could replace the missing code so that it works intended? IF (IsFound (morninglist, child) APPEND (lunchList, child) IF (IsFound (afternoonlist, child) APPEND (afternoonlist, child) IF CCISFound (morninglist, child) OR (IsFound Cafternoontist, child)) APPEND (lunchlist, child) 0 11 stund Cafternoon, Chio) APPER Cutichitat)