Question: Please explain return statement in python ,especially second onr return 1+ anon(n//2).Thank you in advance ! def anon(n): if n%2==1 return 0 else: return 1

Please explain "return statement "in python ,especially second onr "return 1+ anon(n//2).Thank you in advance !

def anon(n):

if n%2==1

return 0

else:

return 1 + anon(n//2)

print(anon(8))

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