Question: Please explain return statement in python ,especially second onr return 1+ anon(n//2).Thank you in advance ! def anon(n): if n%2==1 return 0 else: return 1
Please explain "return statement "in python ,especially second onr "return 1+ anon(n//2).Thank you in advance !
def anon(n):
if n%2==1
return 0
else:
return 1 + anon(n//2)
print(anon(8))
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