please explain this in depth If $5.$ f$($x$)=1$ x $,$ use the definition of the derivative f $($x$)=$ lim h$0$ f$($x $+$ h$)$ f$($x$)$ h to find f $($x$).$ Solution: f $($x$)=$ lim h$0$ f$($x $+$ h$)$ f$($x$)$ h $=$ lim h$01$ x$+$h $1$ x h $=$ lim h$01$ h $($ x x$($x $+$ h$)$ x $+$ h x$($x $+$ h$))=$ lim h$01$ h $$h x$($x $+$ h$)=$ lim h$01$ x$($x $+$ h$)=1$ x$($x $+0)=1$ x $2$