An amplitude modulated (AM) signal is given by PAM (t) = [A + m(t)]cos (wet), let...

 

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An amplitude modulated (AM) signal is given by PAM (t) = [A + m(t)]cos (wet), let m(t) = μA cos(wmt). For μ =0.75, find the power efficiency. A. 100% D. 25% B. 75% C. 22% A single tone AM (DSB+C) modulated signal is shown in the figure below. Calculate the power efficiency (in percentage). A. 12.50% B. 22.22% C. 11.11% D. 33.33% E. 16.67% E. 27.27% A. m(t) = 40 sin (500xt) +20 sin (1000mt) B. m(t) = 20000 π cos (500nt) +20000 π cos (1000xt) C. m(t) = cos (500nt) + cos (1000nt) D. m(t) = 8 sin (500mt) + 4 sin (1000ml) E. m(t) = 8 cos (500mt) + 4 cos (1000ml) 3 0 -3 -9 The following signal is a frequency modulated signal with Ky=20,000 radian/sec/volt. Determine the message signal m(t): PFM (t) = 5cos (2000000nt +40 sin(500nt) + 20 sin(1000nt)) An amplitude modulated (AM) signal is given by PAM (t) = [A + m(t)]cos (wet), let m(t) = μA cos(wmt). For μ =0.75, find the power efficiency. A. 100% D. 25% B. 75% C. 22% A single tone AM (DSB+C) modulated signal is shown in the figure below. Calculate the power efficiency (in percentage). A. 12.50% B. 22.22% C. 11.11% D. 33.33% E. 16.67% E. 27.27% A. m(t) = 40 sin (500xt) +20 sin (1000mt) B. m(t) = 20000 π cos (500nt) +20000 π cos (1000xt) C. m(t) = cos (500nt) + cos (1000nt) D. m(t) = 8 sin (500mt) + 4 sin (1000ml) E. m(t) = 8 cos (500mt) + 4 cos (1000ml) 3 0 -3 -9 The following signal is a frequency modulated signal with Ky=20,000 radian/sec/volt. Determine the message signal m(t): PFM (t) = 5cos (2000000nt +40 sin(500nt) + 20 sin(1000nt))

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Lets solve these stepbystep 1 For the first question the power in the carrier is ... View the full answer