please explain your steps

Question (2): For the code below if the crystal frequency is 20 MHz: EQU Ox7 EQU Instruction Cycle MOVLW D'200 R2 R3 DELAY Ox8 AGAIN R2 D'2500 R3 HERE MOVWE MOVLK MOVWF NOP NOP DECE HNZ DECP BNZ RETURN 1 1 2 1 1 1 2 1 2 R3, F HERE R2, F AGAIN - Find the exact delay fe = 20 MHZ 3 fanss 20 35 MHZ This = 5 us No. of Instructions = 1 +1 +[1+1+(5*250)++2]x200 ++ xi 0:2 MS - 2 + [ 4 + 1250) 200 2 + 1254 * 200 2 50802 Inst. Exact Delay 250 802 +0.2618-6 = 50.16 ms b- Find the approximate (rough) delay Approximated delay > 5*250*200*02 - Soms