please fix and solve the issue my matlab code project : $\%$Mike$\_$id$\_$Project$\_$main.m : Load the DNA sequence

load$(\text{'}$chr$1\_$sect$.$mat'$)$;

dna $=$ chr$1\_$sect$.$dna;

numBases $=$ length$($dna$)$;

$\%$ Find the start and stop codons

startCodon $=[143]$; $\%$ ATG

stopCodons $=\{\text{'}$TAA$\text{'},$ 'TAG', 'TGA'$\}$;

$\%$ Initialize variables to store coding segments

codingSegments $=[]$;

i $=1$;

$\%$ Iterate through the DNA sequence

while i numBases $-2$

$\%$ Check for start codon

if isequal$($dna$($i:i$+2),$ startCodon$)$

$\%$ Start codon found, now search for the stop codon

j $=$ i $+3$;

while j numBases $-2$

if any$($cellfun$($@$($x$)$ isequal$($dna$($j:j$+2),$ x$),$ stopCodons$))$

$\%$ Stop codon found

codingSegments $=[$codingSegments$,$ j $-$ i $+3]$;

break;

end

j $=$ j $+3$;

end

i $=$ j $+3$; $\%$ Move index past this coding region

else

i $=$ i $+3$; $\%$ Move to the next codon

end

end

$\%$ Calculate and print the statistics

totalSegments $=$ length$($codingSegments$)$;

averageLength $=$ mean$($codingSegments$)$;

maxLength $=$ max$($codingSegments$)$;

minLength $=$ min$($codingSegments$)$;

fprintf$(\text{'}$Total Protein$-$Coding Segments: $\%$d

$\text{'},$ totalSegments$)$;

fprintf$(\text{'}$Average Length: $\%\mathrm{.}2$f

$\text{'},$ averageLength$)$;

fprintf$(\text{'}$Maximum Length: $\%$d

$\text{'},$ maxLength$)$;

fprintf$(\text{'}$Minimum Length: $\%$d

$\text{'},$ minLength$)$; Homework Prompt:

DNA Analysis.

In class, we discussed how DNA is a good example of how a huge amount of information can be stored in a vector. In this problem, you will use iteration and logical expressions to analyze a segment of human DNA stored as a $1-$D array. For the sake of programming convenience, you can find the DNA file here $\backslash (\backslash$downarrow $\backslash ).$ uses numeric values instead of the usual alphabetic abbreviations $($A$,$ C$,$ G$,$ and T$)$ as shown in the key below.

DNA Letter to

Number Conversion

Your task is to write a script to calculate the lengths of every protein$-$coding segment in the DNA as shown in the example below.

Part $($a$)$

Begin by downloading the DNA segment file $\backslash (\backslash$downarrow $\backslash )$ on Canvas into your current working directory$/$folder$.$

$-$ Next load the file into MATLAB using the load function as shown below.

$-$ file $=$ load$(\text{'}$chr$1\_$sect$.$mat'$)$

$-$ You can find the size of the DNA array by using the script line:

$-$ numBases $=$ length$($file$.$dna$)$

Part $($b$)$

Iterate through the codons $($the three$-$base segments shown above$)$ in your DNA vector until you identify the location of the start codon: ATG $($or $[143]$ after conversion$).$ After finding the start codon, continue iterating until reaching the first stop codon: either TAA, TAG, or TGA. Record the length of this protein$-$coding segment in a new array and begin looking for the next start codon. We will ignore any new start codons that may appear before we first encounter one of the stop codons.

Note: Remember, it is only meaningful to compare intact codons $($sets of three$)$ starting from the first element in our vector $($we will assume this is the only biologically correct reading dna$(1$:$3)$ and dna$(4$:$6)$ are valid groupings; while dna$(2$:$4),$ which splits up two codons, is not valid.

Part $($c$)$

After reaching the end of the DNA vector, print the following statistics to the command window in the format shown below $($the values shown are for illustration only$)$

$-$ Total Protein$-$Coding Segments: $1300$

$-$ Average Length: $99\mathrm{.}11$

$-$ Maximum Length: $1200$

$-$ Minimum Length: $9$

You are welcome to use built$-$in MATLAB functions mean, max, and min if you find them helpful. As with all things programming, it is much easier to start with a small test case where you know the answer first. Try creating your own DNA vector with the numbers in the above example and confirm that you recover the correct answer before using the full sequence stored in chr$1$ sect$.$mat $\backslash (\backslash$downarrow $\backslash ).$