Question: Please give me a step by dtep solution for my theory of structure assignment. I also typed in the answer I cane up with but

Please give me a step by dtep solution for my theory of structure assignment. I also typed in the answer I cane up with but please fix any mistake and make it clearer. Thank you! Attached is a photo of the figures
Illustrative Problem:
The floor system of a building consists of a 15-cm thick reinforced concrete slab resting on four steel floor beams, which in turn are supported by two steel girders, as shown in the figure. The cross-sectional areas of the floor beams and girders are 94.8cm2 and 337.4cm2, respectively. Determine the dead loads acting on the beams CG
(a) Framing Plan
(b) Load on Beam CC
(c) Load on Bcam DHand DH and the girder AD.
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I tried Solving it and came up with this, is this right?
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(A)
Dead load of concrete slab acting on beam CG.
Volume of slab.=??
Structural weight =23.6kNm3
V=24m2*0.15m=3.6m3
VW=3.6m2*23.6kNm3
=84.96kN
.
(a) Framing Plan
(b) Load on Beam CG
(c) Load on Beam DH
(d) Load on Girder AD
Dead Load of Beam CG
Ainm2=94.8cm2m2
=94.8cm21002
=0.00948m2
volume of Slab =AL
=0.00948m28m
=0.07584m3
Dead Load -VW=0.07584m377kNm3
=5.83968kN
=5.84kN
Total =DLs+DLca=84.96kN+5.84kN
=90.8kN
Load on CG=TL of beam
=90.8kN8m
=11.35kNm
Dead Loads Acting on Beam DH
(B)
Vslab=12m2.15m=1.8m3
Dslab=VslabWco
=1.8mp5236kNm3
=42.48kN
Total Load =DLslab+DLDH,;DLOH=DLca
=42.48kN+5.84kN
=48.32kN
]=[TLLBeam
Dead Load of Girder AD
(c)
AGirder=337.4cm21002
=0.03374m2
Vainder =AL=0.03374m29m
=0.30366m3
DL=VW=0.30366m577kNmss
=23.38182kN=23.38kN
TL=23.38kN9m
=2.59777778kNm
=2.60kNm
With loads 48.32kN acting on points A and D, and 90.8 KN on points B and C.
Please give me a step by dtep solution for my

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