Question: please help - 25 - Section 6.4 Inference for a Difference in Means Question 6 of 18 25 - Section 6.4 Inference for a Difference
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- 25 - Section 6.4 Inference for a Difference in Means Question 6 of 18
25 - Section 6.4 Inference for a Difference in Means Question 6 of 18 View Policies Show Attempt History Current Attempt in Progress 0.25/1 Use the t-distribution to find a confidence interval for a difference in means given the relevant sample results. Give the best estimate for '12, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. - -5.2,Sl - 2.4, 111 = 9 andX2 = 4.7,s2 = 2.5,n2 = 8 A 90% confidence interval for using the sample results xl Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places. Best estimate = Margin of error = Confidence interval : eTextbook and Media Hint Save for Later Attempts: 3 of 4 used Su bmit Answer
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