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Evaluate the definite integral and interpret the result. [ (x3 - 4x) dx -6-5-4-3-2-J 1 2 3 4 5 6X 3; the area between the x-axis and the graph of y = x3 - 4x over the interval [-1, 0] minus the area between the x- axis and the graph of y = x3 - 4x over the interval [0, 2] is 3. 9; the area under the graph of y = x3 - 4x over the interval [-1, 2] is 9. -2; the area between the x-axis and the graph of y = x3- 4x over the interval [-1, 0] minus the area between the x- axis and the graph of y = x3 - 4x over the interval [0, 2] is -- ; the area between the x-axis and the graph of y = x3 - 4x over the interval [-1, 2] is