Evaluate the definite integral and interpret the result. (x3 - 4x) dx -6 -5 -4 -3 -2 -1 1 1 2 3 4 5 6x 9; the area under the graph of y - x3 - 4x over the interval [-1, 2] is 9. O -; the area between the x-axis and the graph of y = x5 - 4x over the interval [-1, 2] is -. the area between the x-axis and the graph of y = x3 - 4x over the interval [-1, 0] minus the area between the x-axis and the graph of y =x5 - 4x over the interval [0, 2] is - 3: the area between the x-axis and the graph of y = x5 - 4x over the interval [-1. 0] minus the area between the x-axis and the graph of y - x3 - 4x over the interval [0, 2] is 3