Question: please help I tried to solve this and kept doing it wrong!!! - -- ----- --- a} ---r----u- 2. [10 marks] At timet = 0,

please help I tried to solve this and kept doing it wrong!!!
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- -- ----- --- a\\} ---r----u- 2. [10 marks] At timet = 0, a tank contains 100 litres of gas with 30 litres of oil mixed in it. Suppose another mixture containing 1 litre of oil per 9 litres of gas is being added to the tank at a rate of r litres/min, and that the gas [oil mixture at is exiting the tank at the same rate. Knowing that the rate of change of oil in the tank, ch' is equal to the rate at which oil is entering the tank minus the rate at which oil is exiting the tank, the differential equation representing this process is 'ven b ' E - L - 5' 3" cit _ 10 100' (a) Use Maple to determine the general solution of the differential equation % = % % given that r = 3 litres/min. dsolve(5'(t)=3/10-3*S(t)/100); 3(t) = [Note: -01 is just the constant of integration 0.] (b) Dene S(t} from part (a) in Maple: S:=(t)->???; [Recalh In general, to enter at in Maple type exp(t);] Now. using the solve(S(0)=???,C); command (substituting appropriately for W?) to solve for 0. state the particular solution to the diEerential equation that satises each of the following initial conditions. Dierential Equation Initial Conditions Particular Solution - (1:) Dene each of the solutions from part (b) in Maple and plot them all on the same plot in Maple for D S t S 100. Include a scan of your Maple plot with your submission. (d) Referring to the graph in (c): i. If 5(0) > 10. will the amount of oil in the tank ever be less than 10 litres? (answer YES or NO) ii. If 3(0)
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