Question: please help. im not sure how to do this... thankyou the question is the first picture The average bond enthalpy for CH is 413kJmol1,413kJmol1 of

please help. im not sure how to do this... thankyou the question is the first picture
please help. im not sure how to do this... thankyou the question
is the first picture The average bond enthalpy for CH is 413kJmol1,413kJmol1
of energy is required to break a mole of CH into atoms.
CH(g)C(g)+H(g),H=413kJmol1 Using this information, and your answer from Part A, calculate the

The average bond enthalpy for CH is 413kJmol1,413kJmol1 of energy is required to break a mole of CH into atoms. CH(g)C(g)+H(g),H=413kJmol1 Using this information, and your answer from Part A, calculate the enthalpy change of the reaction from Part B. That is, calculate the energy required to break only the carbon-carbon bonds in benzene Express your answer to four significant figures and include the appropriate units. Consider benzene in the gas phase, C6H6(g). Use the heat of formation, fH, values below to answer the questions. What is the standard enthalpy change for the reaction that represents breaking all the bonds in gaseous benzene, C6H6(g) ? Express your answer to one decimal place and include the appropriate units. View Available Hintis) What is the chemical equation for the reaction that corresponds to breaking just the carbon-carbon bonds in gaseous benzene, C6H6(g) ? Indicate the phase of each species in your answer. Express your answer as a chemical equation including phases. View Avaliable Hint(s)

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