Question: Please help Learning Goal: Part C - Calculate the deflection What is the deflection of the end of the rod, D ? Let a positive

Please help Learning Goal: Part C - Calculate the deflection
What is the deflection of the end of the rod, D? Let a positive deflection be to the right.
Express your answer with appropriate units to three significant figures.
Figure
1 of 1
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D=
||
To calculate the elastic deflection in an axially
loaded member
For a bar subject to axial loading, the change in
length, or deflection, between two points A and B
is =0LN(x)dxA(x)E(x), where N is the internal
normal force, A is the cross-sectional area, E is
the modulus of elasticity of the material, L is the
original length of the bar, and x is the position
along the bar. This equation applies as long as the
response is linear elastic and the cross section
does not change too suddenly.
In the simpler case of a constant cross section,
homogenous material, and constant axial load, the
integral can be evaluated to give =NLAE. This
shows that the deflection is linear with respect to
the internal normal force and the length of the bar.
In some situations, the bar can be divided into
multiple segments where each one has uniform
internal loading and properties. Then the total
deflection can be written as a sum of the deflections
for each part, =??NLAE.
The circular rod shown (Figure 1) has dimensions d1=6.6cm,L1=6m,d2=3.2cm, and L2=5m with applied loads F1=150kN and F2=55kN. The modulus of elasticity is E=80GPa. Use the following steps to find
the deflection at point D. Point B is halfway between points A and C.
Part A - Reaction force
What is the reaction force at A? Let a positive reaction force be to the right.
Express your answer with appropriate units to three significant figures.
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Part B - Segment the rod
For the given rod, which segments must, at a minimum, be considered in order to use =??NLAE to calculate the deflection at D?
Check all that apply.
View Available Hint(s)
CD
BC
AB
BD
AC
AD
Please help Learning Goal: Part C - Calculate the

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