Question: Please help Let f(x) = 8x + 1 - 3e. Then the equation of the tangent line to the graph of f(x) at the point

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Let f(x) = 8x + 1 - 3e". Then the equation of the tangent line to the graph of f(x) at the point (0, - 2) is given by y = ma + b for m= b = Question Help: Video Submit Question If f(x) = 7x - 6et, find: f' (x ) = f' ( 1 ) = f" (2 ) = f" (1 ) = Question Help: [ Video Submit Question Let f(x) = x (x - 2)9 (22+ 2) 8 Use logarithmic differentiation to determine the derivative. f' (2 ) = f' (2 ) = Question Help: Video Submit Question If f(z) = 8x (x), find f' (5). Question Help: Video Submit Question Let f(x) = - 710g4(x) f' (2 ) = Round your answer to at least 3 decimal places. f' (7 ) = Submit

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