Question: please help me answer all these questions on a piece of paper or ipad. also please ignore any work on the paper as it may

please help me answer all these questions on a piece of paper or ipad. also please ignore any work on the paper as it may be wrong thank you.

please help me answer all these questions on a piece of paper

JWI ters dwe The roller coaster car on the left starts from rest. If the radius of the loop is 11 meters a) How fast does the car need to be going at the top of the loop to get through? b) How large must h be so that this happens? c) If the cart has a mass of 55 kg, what will be the centripetal force on the car when it is at the bottom of the loop? Assume that the value of "h" is what you calculated in part b) * the answer you get will seem very high - .. .Lol Ballersvictor looks are NOT perfect circles. 41.5 . 275 by A volleyball player hits a ball, which has a mass of 275 grams, into the net with a speed of 9.5 m/s. When it rebounds it has a speed of 6.5 m/s in the opposite direction. a. If the ball is in contact with the net for 0.25 seconds, what is the force provided by the net? b. Is the collision elastic or inelastic? How do you know? c. Is energy lost in the collision? How much? # 2 fam ince of A 6,00 gram bullet is fired at a speed of 349 m/s at a block of mane a. What 0.4 m 1.60 kg. The bullet is embedded into the block as we've seen before the string has a length of 40,0 cm, what is the angle that the string wi make with the vertical (as shown). when the block and bullet reach their maximum height? 0. 086 80. 084 B 0.00 ( kg k of mass seen before fram block is attached to a spring with a constant of 750 N/m. It is pulled out (to the right) horizontally a . the string will ance of 25 cm and allowed to oscillate. a. What is the period of this system? What is its angular frequency? c. Write the formula for this system using x(!) = A cos (cut) d. What is the total energy of this system? e. When the block is at +17, cm, how fast will it be going, and in-w : 043 10 035 kg = 0.43 - 1/ 2

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