Question: please help me answer all these questions on a piece of paper or ipad. also please ignore any work on the paper as it may

please help me answer all these questions on a piece of paper or ipad. also please ignore any work on the paper as it may be wrong thank you.

please help me answer all these questions on a piece of paper

# 6 Case 1 Case 2 Two uniform bars of the same dimensions are constructed from the same material. One bar has five evenly spaced holes through it and the second bar has only two holes. The bars are slid over vertical pegs Vertical Vertical and rest on a horizontal surface, where Peg Peg friction between the bar and the surface is negligible. The two bars are each pulled by horizontal forces of equal magnitude F from Top View their right end as shown above. The bars' resulting angular accelerations are recorded. Which case will experience a greater initial angular acceleration? Why? 5 Cuse 1 Same force & same distance from ands of rotation - > same lag 7= Id. lase I has less mess = less . I #7 corsten T, less- I means greare QU Case 1 A new bar with a mass equal to the mass of the cylinder is placed as shown. The bar is released, and its resulting angular acceleration is recorded. Then the cylinder is moved to hang from hole E, as shown in Case 2 at left. Again, the bar is released, and its resulting angular acceleration is recorded. Case 2 Which case will have the greatest angular momentum after the cylinder is released? Why? 3 n turn 1.25 meters at the top of a ramp "- 1 = 2/5mr The roller coaster car on the left starts from rest. If the radius of the loop is 11 meters a) How fast does the car need to be going at the top of the loop to get through? b) How large must h be so that this happens? c) If the cart has a mass of 55 kg, what will be the centripetal force on the car when it is at the bottom of the loop? Assume that the value of "h" is what you calculated in part b) ** the answer you get will seem very high - because it is! Roller coaster loops are NOT perfect circles. IMM = my

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