please help me answer these short questions, i don't need any type of explanation just simple answers you don't have to explain how you did it. They are just short questions.

1.

Let s: {1, o, 2, 4, 7}. M =1 g(x) = 2x+1 W ii _ x2+1 km i 3 J Click and drag to identify the sets on the right with the function images on the left. {(5) {1,2,5} :] {0,1,2} 9(8) {-1, 1, 5, 9, 15} i7(3) k($) {1} :] {-2l 1' 3' 6' 8} Identify the correct statements for the given functions from the set {a, b, c, d) to itself. (Check all that apply.) Check All That Apply fa) = b, Ab) = a, fc) = c, fd) = dis a one-to-one function, as each element is an image of exactly one element. fa) = b, Ab) = a, f(c) = c, fd) = d is not a one-to-one function, as a is mapped to b and b is mapped to a. fa) = b, fb) = b, fc) = d, fd) = c is a one-to-one function, as each element is mapped to only one element. fa) = b, fb) = b, fc) = d, fd) = c is not a one-to-one function, as b is an image of more than one element. fa) = d, fb) = b, fc) = c, fd) = d is a one-to-one function, as each element is mapped to only one element. (a) = d, Ab) = b, fc) = c, Add) = d is not a one-to-one function, as dis an image of more than one element.Let 1(X) = x2 + 1 and g(X) = X+ 2 be functions from R to R. If f(g(x)) = x2 + Ax+ B and g(f(x)) =x2 + CX+ D, then match the unknownsA, B, C, and Don the right to their corresponding values on the left. Match each ofthe options above to the items below. 4 V 5 v 0 v Let fbe a function from A to B and S be a subset of B. Identify the correct steps involved in showing that f-(S ) = f-1 (S) . (Check all that apply.) Check All That Apply We know that S = B - S and f-1 (S ) = A -f-1 (s). We know that S = A - S and f-1 (S ) = B-f-1(s). Let x Ef- (S) . This means that f (x) E S or equivalently that f(x) & S. Therefore, by the definition of inverse image, x # f(S); so, x E f-1 (S) . Therefore, by the definition of inverse image, x E f(S); so, x E f-1 (S).Arrange the steps in the correct order to prove that if X is a real number and m is an integer, then [x + m] = [x] + m. Rank the options below. Suppose that [x] = n , where n is an integer. Using the property [x] = n if and only if n 1