Question: Please help me answer this question, so I will know my answer is right before I submit it... Part II - IP Fragmentation Net 1
Please help me answer this question, so I will know my answer is right before I submit it...



Part II - IP Fragmentation Net 1 Net 2 Net 3 A B R MTU = 3000 MTU = 1500 MTU = 540 Figure 1 Station A needs to send a data size of 2700 bytes to station B across the networks as shown in Figure 1. Data needs to be fragmented because it is too big to fit the MTU size in Net 2 and Net 3. Show the value of the following fields for each of the resulting fragments at station B. Assume that the fragments (all but the last one) have the maximum possible size. The Identification value is 4779 and the HLEN value is 20 bytes. a) b) Total length. Identification. More fragments flag. Fragment offset. First byte. Last byte. d) e) f) (25 marks) NET 2: MTU 1500 FRAGMENT ID FIRST BYTE LAST BYTE TOTAL LENGTH FRAG.OFFSET M FLAG 1 2 NET 3: MTU 540 FRAGMENT ID FIRST BYTE LAST BYTE TOTAL LENGTH FRAG.OFFSET M FLAG 1.1 1.2 1.3 3 NET 3: MTU 540 FRAGMENT ID FIRST BYTE LAST BYTE TOTAL LENGTH FRAG.OFFSET M FLAG 2.1 2.2 2.3
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
