Question: please help me answer this topic is Defining Hyperbola and Determining Its Standard Equation Form 81x - 63y + 252y - 5000y - 5355 =

 please help me answer this topic is Defining Hyperbola and Determining

please help me answer this topic is Defining Hyperbola and Determining Its Standard Equation Form

Its Standard Equation Form 81x - 63y + 252y - 5000y -

81x - 63y + 252y - 5000y - 5355 = 0 E Learning Task 3: Identify the length of transverse axis and conjugate axis, and the orientation of the given standard form of the equation of a hyperbola. (x+ 3)2 (1+1)= 1. 25 16 2. 169 3. 49 15 Learning Task 4: Identify parts, standard form and general form of the equation of a hyperbola given its specific condition. 1. Find the parts of a hyperbola whose center is located at (-6, -3), one of its foci is located at (-11, -3) and one of the endpoints of the conjugate axis is located at (-6, 0). 2. The center of a hyperbola is at (-4,1), one of the vertices is at (-4,3) and the length of the conjugate axis is 6 units. 33 PIVOT 4A CALABARZON Learning Task 5: To find the answer, find the parts of a hyperbola given the standard general form of its equation. Write the corresponding letter on the box above the correct answer in the decoder. Decode the Answer It is an hour-glass shape, which means that it has two hyperbolas one on each side. (x - 1)= (y -1)2 =1 1. 12 Orientation: Letter Parts Answer P Center K Vertices Endpoints of Conjugate Axis T Foci Equation of Asymptotes Graph: D 2. 121y - 4x3 - 484 - 0 Orientation: Letter Parts Answer o Center R Vertices Endpoints of Conjugate Axis W Foel Equation of Asymptotes Graph: (3, 1) & (1, 1 + 2V/3 (0, 0) (11, 0) & (1, 1) (0, 0) (0, 2) & (5, 1) & (-1, 1) (1,1- 2V/3) (-11, 0) (0, -2) (-3, 1) (5, 1) & (0,5v5) (-3, 1) (0, 0) (11, 0) & (0, 2) & (0,-3V5) (-11, 0) (0, -2) PIVOT 4A CALABARZON 34

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