Please help me based on previous solution

Show solution Solution We have Q (t ) = / 3 dt=. 3t In 3 + C. Then, at t = 0 we have Q(0) = 10 = 1 In 3 + C, so C ~ 9.090 and we get 3t Q(t ) = In 3 + 9.090. At time t = 2, we have 32 Q(2) = In 3 + 9.090 ~17.282. After 2 hours, there are 17,282 bacteria in the dish. ? Exercise 5.6.5 From the previous Example, suppose the bacteria grow at a rate of q(t) - 2". Assume the culture still starts with 10, 000 bacteria. Find Q(t). How many bacteria are in the dish after 3 hours? Q (t) = In (22t) + 8.557 x Q(3) ~20099 X