Question: please help with the blanks HW 27.1) Hand Calculation for SNK, Drawn from Lecture Notes: Week 12, Day 3 and Week 13 Day 1 27.1)

please help with the blanks
please help with the blanks HW 27.1) Hand Calculation for SNK, Drawn
from Lecture Notes: Week 12, Day 3 and Week 13 Day 1

HW 27.1) Hand Calculation for SNK, Drawn from Lecture Notes: Week 12, Day 3 and Week 13 Day 1 27.1) A botanist used a completely randomized design to allocate 35 individually potted carrot plants to 5 different soil treatments. The observed variable was the total dry plant weight without roots in grams after 31 days of growth. See the summarized data in the table below: Treatment: Mean: 4.34 7 B 4.89 7 5.24 7 D 3.78 7 E 5.86 7 n Given an MSW = 0.29, use the Student Newman Keuls test to determine the respective size of each mean using a line code summary. See page 791 for the Newman Kuels Table. 27.1a) Based on the table above, there are 10 possible pair-wise comparisons from these five groups and the dfw are: dfw= 27.1b) Use the table below to indicate the ascending order of the group means: T T 18 A 00 Select subscripts for an I ascending order of means: T? 3.78 Ascending sample 5.24 means: D E 4.34 4.89 5.86 27.1c) Use the table below to determine the sample value and critical value for each paired mean comparison. Then based on this comparison determine whether the compared means are statistically equal according to the Newman Keuls test at an LOS of 5%. See page 791 for the Newman Kuels Table. Steps apart: SNK Table Value 12? X?= Absolute >? Difference or NK Critical Value These paired means are: 2 == not equa 2 2 equal 4 = not equa 2. > > > 4 not equa 2 = not equa 5 > not equa HW 27.1) Hand Calculation for SNK, Drawn from Lecture Notes: Week 12, Day 3 and Week 13 Day 1 27.1) A botanist used a completely randomized design to allocate 35 individually potted carrot plants to 5 different soil treatments. The observed variable was the total dry plant weight without roots in grams after 31 days of growth. See the summarized data in the table below: Treatment: Mean: 4.34 7 B 4.89 7 5.24 7 D 3.78 7 E 5.86 7 n Given an MSW = 0.29, use the Student Newman Keuls test to determine the respective size of each mean using a line code summary. See page 791 for the Newman Kuels Table. 27.1a) Based on the table above, there are 10 possible pair-wise comparisons from these five groups and the dfw are: dfw= 27.1b) Use the table below to indicate the ascending order of the group means: T T 18 A 00 Select subscripts for an I ascending order of means: T? 3.78 Ascending sample 5.24 means: D E 4.34 4.89 5.86 27.1c) Use the table below to determine the sample value and critical value for each paired mean comparison. Then based on this comparison determine whether the compared means are statistically equal according to the Newman Keuls test at an LOS of 5%. See page 791 for the Newman Kuels Table. Steps apart: SNK Table Value 12? X?= Absolute >? Difference or NK Critical Value These paired means are: 2 == not equa 2 2 equal 4 = not equa 2. > > > 4 not equa 2 = not equa 5 > not equa

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