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The van der Pol equation is a second order ODE given by where > 0 is a scalar parameter. We can rewrite this equation as a system of first-order ODE's by making the substitution. The resulting system of first-order ODE's is We can write the above as y'-foy) where the bold notation means a vector The function file below represents the van der Pol equation using. The variables n and are the entries y(1) and y(2) of a two-element vector, function f deriv(t,y) Solve the ODE using the ode45 function on the time interval [0 20] with initial values [2 0]. The resulting output is a column vector of time points, t, and a solution array y. Each row in y corresponds to a time returned in the corresponding row of t. The first column ofy corresponds to n and the second column to . [Ly] ode45(@deriv.[0 20].[2; 0]); Plot a phase plot where y(1) vs y(2) for various values of but including =1. Describe the behavior as is varied. Redo the above using Euler's Method and comment on the differences