Please interpret this C assembly code to figure out what the password is for the binary bomb. Please provide the correct answer. Thank you

phase 2: push edi push esi push ebx sub esp, 8x28 (var_34) nov eax, dword gs:[8x14] nov dword [esp+ex24], eax xor eax, eax (8x8 lea eax, [esp+8xc (var_28)1 push eax push dword [esp+exc (arg1]] call read_six_numbers add esp, ex18 (var_2c) p dword [esp+9x4 {var-28)], 8xf3 8x 8848 bed call explodo _bonb Does not return lea edi, [esp+x18 (var_14)] mov esi, 8x55555556 ecx, dword [ebx] ax, ecx mav ecx, ex1f edx, ecx cmp dword [ebx+0x4], edx 0x 8348 cef ebx, 8x4 ebx, eds ex8848 bfa call explode bonb Does not return jne eax, dword [esp+8x1c] mov xor eax, dword gs:[8x14] 0x8848c 28 add call I Do esp, x28 { saved-ebx) stack_chk fail es not return ebx popesi pop edi