Question: Please make sure code is running correctly, ive posted this multiple times and always doesnt work for me. You only need to define the get_word_len_dict()
? # 2222222222222222222222222222222222222222222222222 get-word-len-dict() Define the get_word lendict() function which is passed a string of text as a parameter. The function returns a dictionary with keys which are integers and corresponding values which are lists of unique words. The list of words corresponding to a key contains all the unique words from the text that have a length equal to the key value. The corresponding lists of unique words should be in sorted alphabetical order Note: the testing code makes use of the print_dict_in _key_order (a dict) which prints the dictionary pairs in sorted key order For example, the following code: text"May your coffee be strong and your Monday be short" the dict get word len dict(text print_dict_in _key_order (the_dict) print() text 'why does someone believe you when you say there are four billion stars but they have to check when you say the paint is wet the dict get _wordlen dict (text) print_dict_ in_key_ order (the dict) prints: 2 be' 3 'May 'and 4 'your' ] 5 'short' ] 6 'Monday "coffee strong ] 2'is' to' 3 'are'"but, say, 'the wetwhy you' 4 : 'does 'our', 'have',theywhen' 5 'check, "paint, 'starsthere 7'believe, 'billion, someone def get_word len dict(text): return fh
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