*Please only answer if you know the answer I'm very strapped for time**To avoid confusion please highlight, circle, or box in the correct answer, that way I can differentiate between work and the correct answers*

Find the area of the surface generated by revolving the curve y = 1 2x - x , 0.5sxs 1.75, about the x-axis. -. . The area of the surface generated by revolving the curve y = v2x -x , 0.5sxs 1.75, about the x-axis is square units. (Type an exact answer, using it as needed.)