Please proof my calculations by using Software MATLAB Only

My Question which I already calculate in the first picture, ( and my calculation in 2nd and third picture)

X 3) Find the equation of the normal curve of y = tan at x = 3 i. Find slope of the tangent at x = 3 ii. Find slope of the normal at x = 3 iii. Find equation of the normal iv. Plot graph y = tan tangent and normal at x = 3 on the same plot. sol @ Given 3. tar! (2/4); 733 de 3 ( tant2) - klare bancord] df. de rule affre) dx Apply The chain U- 2 f- arc tan (u) ( Apply The common derivative dee d Caritan (u) = u71 mi se (5) u 2 Substitut back - (3) dx 171 otola 274. 2 171 1 x74 Tangent slope Slope- dy 274 da wir 13 at x=3 dy de = 374 3x Slope of Tangent ma 1 13 Slope of normal lone m l x slope of Tangent line (m] =1 normal line at 23 slope of 0i) m xm =- m, x 73 1 / m = slope of roomd line Comm.) = -1 2-3 (iii) Given tant ( 2 ) = = 6.48279 Than y= point= (3, 0.982790) Slope of normal line (m1 = -8 The equation of Normal line (YY) = m(x-2) (4 - 0.9 3219-- ) = =B (x-3) y = -132 +39 +0.98272~.. A y = -12 + 20.48272--- y-axi's @y-aritan (4) -lo