Please proof my calculations by using Software MATLAB Only

x -1 3) Find the equation of the normal curve of y = tan at x = 3 2. i. Find slope of the tangent at x = 3 ii. Find slope of the normal at x = 3 iii. Find equation of the normal X iv. Plot graph y = tan tangent and normal at x = 3 on the same plot. soli- @ Given tar! ( 2 ); 3. 793 en (tan-3) (ase tamx) ] df. de rule affre) dx Apply The chain U- 2 f = arc tan (2) The common CS Apply derivative d Caritan (u) uzi dee wt (3) substitet back u 2 (3) dx 171 bila x74. 2 171 1 2 x74 Tangent slope Slope dy 274 da dy 13 at x=3 = 374 da 3x of Tangent Slope m - 1 13 Slope of normal line m 1x slope of Tangent line (m] =1) Slope of normal line (n) = -13 point= (3, 0.98279 -2) normal 253 slope of 001) m xm =- m, x 73 1 / m = Slope of normal line Com:) = -2 29 Given tant(*) = = 6.98279 Than y= The equation of Normal live (MY I = m(x-2) (4 - 0.9 3219-- ) = = (x-3) y = -132 +39 +0.98279~-. AU! y = -132 + 20.48212--- y-axi's 6. Y aretan (2) -lo