Please see table below for both prol

$\backslash$table$[[$Points$,$X Coordinate,Y Coordinate,Z Coordinate$],[$Reservoir$,9900555\mathrm{.}61,747238\mathrm{.}53,3834\mathrm{.}72],[$House A$,9901191\mathrm{.}55,746943\mathrm{.}95,3787\mathrm{.}23],[$House B$,9901191\mathrm{.}55,747079\mathrm{.}82,3768\mathrm{.}36],[$House C$,9901191\mathrm{.}55,747162\mathrm{.}74,3760\mathrm{.}25],[$House D$,9901191\mathrm{.}55,747100\mathrm{.}74,3768\mathrm{.}77],[$House E$,9901191\mathrm{.}55,746973\mathrm{.}16,3798\mathrm{.}87],[$House F$,9901191\mathrm{.}55,747259\mathrm{.}59,3750\mathrm{.}53],[$House G$,9901191\mathrm{.}55,746922\mathrm{.}62,3790\mathrm{.}63],[$House H$,9901191\mathrm{.}55,746894\mathrm{.}93,3798\mathrm{.}28]]$

Up in the mountains, in the 'cold' climate, the assumed water use is $75$ liters per person per day. For now, we can assume $5$ people per house, which is generally a conservative estimate. Calculate median flowrate $\frac{m^3}{?}$ second from the above information. Now assume that the peak day flow is $1\mathrm{.}25x$ the median flowrate and the peak flow is $3x$ the median flowrate. Finally assuming the reservoir elevation given in the above table is the maximum water level in the morning and the minimum water level is $2m$ below that in the evening please calculate the peak day flow rate and the peak flow rate for houses $A-H$ based on how you calculated based on HW #$2$ and check the adequacy of water levels in the reservoir to supply water to houses A$-$H$.$