Question: Please show full solutions thank you !! 2. Let tan z = siz be the function tangent of a complex argument z. It is not
Please show full solutions thank you !!

2. Let tan z = siz be the function "tangent" of a complex argument z. It is not injec- tive, so its "inverse" arctan z is defined as the multivalued function that satisfies the equation tan(arctan(z) ) = z. (i) Express arctan z in terms of log z. (ii) If g(z) is a branch of arctan z which is continuous at zo, prove that g(z) is differentiable at zo and find g'(zo). (iii ) Show that Arctan z := 2, Log 1-12 1tiz is a brach of arctan z and find the region D C C in which Arctan z is defined. 3. Find a branch of the multivalued function f(z) = (23 + 1) 3 defined (and holomorphic) in the region D = C\\(I1 U I2 U 13), where I1 = [-1, 0] is the interval on the real line, I, is the closed interval connecting the origin with the point , + 23, and I3 is the closed interval connecting the origin with the point , - 213. Express your answer in terms of the principal brach of the log-function. Hint. Study the map 4 : Cx - C defined by y(z) = 1 + 3 is a 3-to-1 map from D onto C R
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
