Question: Please show how to get these values in the table. Given: =0.652670905RNH3=56791.1128kmol/m3.hrA=706m2FN2=135.43kmol/hrX(0)=0 Question: Solve dLdX=2FN2RNH3A using 4th order Runge Kutta method and plot a Conversion

Please show how to get these values in the table. Given:

Please show how to get these values in the table.

Given: =0.652670905RNH3=56791.1128kmol/m3.hrA=706m2FN2=135.43kmol/hrX(0)=0 Question: Solve dLdX=2FN2RNH3A using 4th order Runge Kutta method and plot a Conversion (X) vs Length (L) graph

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