Please show steps on how to solve the question below:

Let xpbar = The proportion of the your population you are trying to determine (x / n).

For example, if you are trying to determine the proportion of your population that holds a favorable view of the President Of The United States (POTUS), then xpbar = the number of people in your poll responding "favorable" (x) divided by your sample size (n).

Let p = The true proportion of the population you are trying to determine. For our purposes, we will set p equal to the xpbar you determined and find the confidence interval around it.

The Standard Error of the Proportion, p = p (1 - p) / n= p (1 - p) / n

The transformation formula for comparing a sample proportion (xpbar) to the population proportion (p):

Z = (xpbar - p) / pso by extension Z = (xpbar - p) n / p (1 - p)

1)Suppose survey and decide to construct the entire poll differently. You ask 10,000 people face to face and across urban and rural population centers and across the USA and near schools, athletic, cultural and religious venues, and outside government, financial, manufacturing and technology office areas and try to get responses from individuals across different age and socio-economic characteristics. When you are done you find that 40% of your sample has a favorable view of the POTUS. With 95% confidence, what can you say is the interval containing the true proportion of the total population that hold a favorable view based on this newly constructed poll results. { Please show both your bounds as decimals to four places }