Question: please show work so i can follow the steps and procedures. Thanks in advance NOTE YOU MUST SHOW YOUR WORK FOR FULL CREDIT! *Answer Questions
"NOTE YOU MUST SHOW YOUR WORK FOR FULL CREDIT! *Answer Questions on a separate Sheet of Paper! 1. (5 points) How many micrograms of solid MgCl, (Formula Weight: 95.21 lg mole) are required to prepare 150ml. of a 250mM solution? 2. (15 points) If you disolve 150mg placese (Formula Weight: 180.16 mole) im 118m1 of water (all answers must be presented in scientific notation format); a. What is the concentration of glucose in mM and M? b. If you take 25ml of this solution and dilute it to Som, what is the concentration of the glucose in the resulting solution in M? c. How many nanomoles of glucose are present in 10mL of the diluted solution? 3. (5 points) Convert the concentration below to mM and M 1.25mg of sucrose (Formula Weight: 342.30g/mole) per 91ml 4. (10 points) What molarity of HCI stock solution is needed so that 0.5ml of this stock solution diluted to 0.005L will yield 25mM? 5. (10 points) You have to make 30ml of 0.05M HCI from a 10M HCI stock solution, but the only measuring devices available are 100ml graduated cylinders and 10ml. serological pipets. How could you nocurately make the dilute HCI solution? 6. (25 points) You have a 0.25M sock solution of NaCl (Formula Weight: 58.4g/mole), 0.5M stock solution of glucose (Formula Weight; 180.2g/mole), and a bottle of solid Tris base (Formula Weight: 121.1g/mole). How would prepare (be specific) 150ml. of a single solution containing 10mM Tris, SmM glucose, and 75mm Naci 7. (10 points) Describe how you would prepare 250mlof a 0.5M stock solution of potassium chloride (Formula Weight: 74.55g/mole). Using this stock solution, describe how you would prepare 150ml. of the following dilutions: 2.5mM and 5000mm 8. (10 points) How many milligrams of MyCI, (Formula Weight: 95.211g/mole) are contained in 50mL of 50mM MgCl, (swer must be presented in scientific notation formaty? 9. (10 points) What is the molar concentration of sodium chloride (Formula Weight: 584 g/mole) in a 12% (w/v) solution
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