Question: Please solve all the paragraphs 1. Assume a memory location (1 byte) of address 0378H containing the status of eight running machines. A working machine
1. Assume a memory location (1 byte) of address 0378H containing the status of eight running machines. A working machine is with status 1 and a machine failure is with status 0 . A machine can start (passing from 0 to 1 ) or fails (passing from 1 to 0 ). Assume once again that only one machine can change status at a time. Write an 8086 Assembly language program to continuously read the status of the machines. In case of status change, the program determine the number of that machine (from 0 to 7 ) and display it on the screen. Steps : a) Read the content of the memory of address 0378H using direct addressing mode. b) Compare the current status with the previous one. If there is a change : 1) Determine the number N of the machine status change, 2) Convert the number to ASCII (Just Add 30H), 3) Display on the screen The message "The machine Number N change of status." Use the Function 09H,Int21H to display the message on the standard output
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