Question: please solve and explain Consider the following system at equilibrium where H=111kJ, and Kc=6.3010, at 723K : 2NH3(g)N2(g)+3H2(g) If the temperature on the equilibrium system
Consider the following system at equilibrium where H=111kJ, and Kc=6.3010, at 723K : 2NH3(g)N2(g)+3H2(g) If the temperature on the equilibrium system is suddenly decreased: The value of Kc increases decreases remains the same The value of Qc is less than Kc is greater than Ke is equal to Kc The reaction must run in the forward direction to reestablish equilibrium run in the reverse direction to reestablish equilibrium remain in the current position, since it is already at equilibrium The concentration of H2 will increase decrease remain the same
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