Question: please solve, I appreciate ur help! L.P. Model: Q Minimize 24 22 20 18 Z = 20X15Y Subject to 7x + 11466 (C) 16x +4Y280
please solve, I appreciate ur help!
L.P. Model: Q Minimize 24 22 20 18 Z = 20X15Y Subject to 7x + 11466 (C) 16x +4Y280 (C) XY20 On the graph on right, constraints, and have been drawn. Using the point drawing tool, plot all the corner points for the feasible area 10 12 104 . 4 2- 8 10 12 14 10 18 20 22 24 A series of parallel lines for different values of the objective function (iso-profit line) is shown to the right. An optimal solution to any LP problem will lie on a boundary or at a corner point of the feasible region. The closer the line lies to the 0 origin, the lower the value of the objective function (iso-profit line) will be. The lowest line that still touches some point of the feasible region will pinpoint the optimal solution. In this problem, the optimal solution is point 3 Apply the method of simultaneous equations to the two constraint equations to solve for the optimal solution: 7X + 11Y = 66, 16x + 4y = 48. = 7X + 11Y = 66, 16X + 4y = 48. The optimum solution is: X = 1.79 (round your response to two decimal places). Y = 4.84 (round your response to two decimal places). Substitute X = 1.79 and Y = 4.84 into the objective function. Z = 20X + 30Y 20(1.79) + 30(4.84) (round your response to two decimal places)


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