Please solve it in a different way than the solutions below?

For one type of spare part purchased in parcels; It is known that the number of pieces (X) that do not meet the standards in each parcel is a random variable with an average of 2 and a variance of 3. If the repair cost of a part that does not comply with the standards is X^2 Turkish liras, what is the average repair cost per parcel?

Answer 1 of 1 Done Define , X: No. of pious that doesn't comply with the standards in each pereel. 165 given that mean and variance of X are 2 and 3 respectively .. E(X)=2 Var(x)=3 The repair cost to bring non-coroplicent parts to standard 15 - + ... The arrope sepies contine will be . ECx2) To find Exy :- Vark) = 3 E6x7 - [E60] =3 - Exy - 2 =3 EX") = 4+3 E(X) = 7. .. The average repair cost will be Anbeves f Expert Q&A + N N N N N N NO NO N 86 2 0.551976 1.732 3.732 87 2 0.978745 5.12 7.12 88 0.463511 0 2 89 0.428234 0 2 90 2 0.100395 -1.732 0.268 91 0.760933 3.464 5.464 92 2 0.929373 3.464 5.464 93 0.391512 0 2 94 2 0.628139 1.732 3.732 95 2 0.57647 1.732 3.732 96 2 0.908902 3.464 5.464 97 2 0.212639 0 2 98 2 0.523308 1.732 3.732 2 0.801147 3.464 5.464 100 2 0.511058 1.732 3.732 Average cost per part 7.14008 Therefor average repair cost will be around 7.14 TL Note: 1. The random number generated using the formula: ra 2. The S.D calculated using the formula: =IF(N3