Question: please solve Solve the following second-order initial-value problem. y + 9y = cos(5t) + 26(t - #). y(0) = 0 = y'(0) O y(t )

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Solve the following second-order initial-value problem. y" + 9y = cos(5t) + 26(t - #). y(0) = 0 = y'(0) O y(t ) = 1 -16 [cos(5t) - cos(3t)] + Un/2(t) sin( 3( t - 2 O y(t) = 1 -16 [cos(5t) + cos(3t)] -= -UT/2 (t) sin( 3(t - I 2 O y(t) = 1 -16 [cos(5t) + cos(3t)] - Un/2(t) Cos ( 3 t - TE O V(t) = -16 [cos(5t) - cos(3t)] + -Up/2(t) sin( 3( t -. 4 2 O (t) = 1 -16 [cos(5t) - cos(3t)] + -Un/2(t) cos( 3( t - 3

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