Question: Please solve step by step and Don't use ChatGPT and Do not use old chegg answers.. All info given Topics covered: polynomits, Euclidean rings, division,

Please solve step by step and Don't use ChatGPT and Do not use old chegg answers..
 Please solve step by step and Don't use ChatGPT and Do
All info given

Topics covered: polynomits, Euclidean rings, division, reduction modulo p. 3.1. Let A be a commutative associative unital ring, A[x] be the ring of polynomials in one variable x with coefficients in A. Let f=a0+a1x++anxn be a polynomial. Prove the following propositions. A. f is invertible in A[x] if and only if a0 is invertible in A and a1,,an are nilpotent B. f is nilpotent if and only if a0,,an are nilpotent. C. f is a zero divisor if and only if there exists a nou-zero element aA such that af=0. 3.2. A. Show that K[x] ( K a field) is a Euclidean ring 2 with respect to the Euclidean function N(f)=deg(f). B. Similarly, show that the ring of Gaussian integers Z[i]C is Enclidean with respect to the function N(a+bi)=a2+b2. C. Do the same for the so-called Eisenstein numbers which are complex numbers of the form a+b,a,bZ and =e12 the primitive eube root of unity. The Euclidean function is given by f(a+ba)=a2ab+b2. 3.3. A non-zero non-invertible element p of an integral domsin A is called irreducible if it cannot be represented as a product p=ab with a,b non-invertible. Irreducible elements of K(x) are known as irreducible polynomials. Let A be a Euclidean ring. Then if an irreducible element p divides the product a1an then there is a factor ai such that p divides ai (i.e. irreducible elements of A are prime elements). 3.4. Prove that in a Enclidean ring A every non-zero non-invertible element can be factored into a product of irreducible elements, with the decomposition being essentially umique (i.e. unique up to permutation of factors and multiplication by invertible elements). 3.5. (Gauss's lemma) Prove that if a polynomial fZ[x] with integer coefficients is a product f=gh of two polynomials g,hQ[x] with rational coefficients then f is a product of two polynomials g~,h^ proportional to g,h respectively such that g~,h^ are polynomials with integer coefficients. "Recall that an element a of an associative ring is nilpotent if there exists a powitive intecer n such that a=0. 2 It folkws from the previous problem that K[x] is a domain when K is a domaia, in porticular a feld

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