Please solve this problem. It requires the use of Augmented Matrix during the calculation of its solution.

A lab group was supposed to make 14 mL of a 36% acid solution by mixing a 20% solution, a 26% solution, and a 42% solution. However, the 20% solution was mislabeled, and was actually a 10% solution, so the lab group ended up with 14 mL of a 34% acid solution, instead. If the augmented matrix that represents the system of equations is given below, what are the volumes of the solutions that should have been mixed? Volume of 20% solution = Ex: 5 # mL Volume of 26% solution = mL Round to the nearest whole number. Volume of 42% solution = ml Show transcribed data Expert Answer 10 This solution was written by a subject matter expert. It's designed to help students like you learn core co Anonymous answered this 3,411 answers Lot x denote amount of 201 solution mixed . 26 7. Z 42% Now x +y+2=14 Xx 20 + y x26 + 2x42. = 14x36 106 100 100 100 . ~ 10x + 13y + 212 = 252 - 12\f24 = 147 4 -2 S also 13 4 + 21 2 = 2 24 18 4 14 4 4 - 132 +2 12 = 224 5 13x7 +2 = 28 S Z = 28 - 91 140 - 91 S 4 9 - 9 . 8 S S clome. but in 4 = 56 - 49 1 = 1.4 ime. S Volume of 20 % Sel = 3 ml 26 10 Sol = 1 me 42 7 sud = 10 ml.A lab group was supposed to make 9 mL of a 21% acid solution by mixing a 17% solution, a 30% solution, and a 40% solution. However, the 17% solution was mislabeled, and was actually a 7% solution, so the lab group ended up with 9 mL of a 13% acid solution, instead. What are the volumes of the solutions that should have been mixed? Volume of 17% solution 2 mL . Round answers to Volume of 30% solution 2 mL one decimal place. Volume of 40% solution 2 mL . 2