Please tell me how to solve below problem's b)

1) b)

V = P3. W = all p(a) in V with p(1) = 0 and 0 = xp(x)d . 1 a) dim (W) = 2 Part 2 of 2 b) find two elements of P3 that form a basis for W. Use only integer coefficients in your answer. (Hint: If your basis element has fractions in it, you can replace that basis element by a non-zero multiple) p(z) = q(a) =V Part1of2 V : R232. W: allAianithA[1 1] = [1 11A. 1 D 1 0 a,diE(W)=- Part 2 of 2 b) Two elements of R2z2 that form a basis for W are 41: V Part 1 of 2 V = P4. W = all p(x) in V with p( - a) = p(x). (Functions with this property are said to be "even") a) dim (W ) = 3 Part 2 of 2 b) find three elements of P2 that form a basis for W. PI(z) P2(x) = P3 (x) =V Part 1 of 2 V = P4. W = all p(x) in V with p( - x) = -p(x). (Functions with this property are said to be "odd") a) dim (W) 2 Part 2 of 2 b) find three elements of P2 that form a basis for W. PI (ac) = p2(a) =