Question: Please Use MATLAB and post the code as the answer 1. 2002 Nco, = x 2-x = 6.76-0.5x Poz 1-0.5x = NT 6.76-0.5x Pcoz NCO2

Please Use MATLAB and post the code as the answer

Please Use MATLAB and post the code as the answer 1. 2002

1. 2002 Nco, = x 2-x = 6.76-0.5x Poz 1-0.5x = NT 6.76-0.5x Pcoz NCO2 NT 6.76-0.5x Determine the equilibrium conversion for 200 + O2 If stoichiometric amounts of CO and air are reacted at 2000 K and 1 atmosphere pressure. At 2000 K the equilibrium constant for this reaction is 62.4 x 106 atm. As a basis, consider 2 gmoles of CO. Then there would be 1 gmole of O2 and 3.76 gmoles of N2. Performing a mole balance on each species and defining x as the amount of CO that reacts yields Nco = 2 - X No, = 1-0.5x Then the partial pressures are given as Nco Noz Pco = NT Substituting these results into the equilibrium relationship yields x2(6.76 0.5x) K = 62.4 x 106 PicoPo2 (1 0.5x) (2 - x)2 assuming the standard state fugacities of CO2, CO and O2 are unity. Rearranging into a normalized form gives x2(6.76 -0.5x) 1 62.4 x 106(1 0.5x)(2 - x)2 a. Solve for the equilibrium composition to three significant figures accuracy using Newton's method with a starting point of x = 0.1 g mole b. Solve this problem using the Illinois method C. Solve this problem using a built-in function from MATLAB. PE02 - =

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