please write down the code in *c* , no need to extra explanation

Complete the program in blank box given below with appropriate C statements that ask a user to enter o negative integer and ends with 0. Based on the entered data, calculate the percentage of negative integers greater than-10. Somple output of the completed code is as follows in Figure 2: Enter a positive integer or -1 to stop: 9 9 is less than 10! Enter a positive integer or -1 to stop: 8 8 is less than 10! Enter a positive integer or -1 to stop: 23 23 is not less than 10 Enter a positive integer or -1 to stop: 6 6 is less than 10! Enter a positive integer or I to stop: 5 5 is less than 10. Enter a positive integer or -1 to stop:-1 The percentage of positive integers less than 10 entered is 80.0%! Figure 2: Sample of completed code Your answer should follow the format given below, int main() // Variables definitions W/ Prompt user to enter data with the following message and display the entered data W "Enter a positive integer or -1 to stop: W Colt the part of Integer that