Pls answer all blanks and only if u r 100% sure it's right.

The formula As = AQ/T only works at constant temperature. A key question of interest would be looking at the change in entropy as an object itself undergoes a temperature change. To do this we would need to look at the above formula in little chunks of As , each small enough to assume that the T was more or less constant over that interval, and then add up the chunks. If we think about that in calculus terms, then the As terms will be ds, and the sum of the little chunks will be an integral. In other words, As=fds=fdQlT It's easier to approach that formula if we recognize that a change in temperature is related to a heat transfer by: q=chT Recasting this work into an integral over T, fill in the blank to find the integral that expresses the change in entropy: As=f dT Now assume we have a pair of objects made out of a metal that has a specific heat of 355 J/kg/K. To make calculations simpler, each has a mass of 5 kg. The hotter one starts at a temperature of 359 K, and the colder one 301 K. If they are placed in contact, what is their final temperature? K. What is the change in entropy of the hotter object? J/K. What is the change in entropy of the colder object? J/K. What is the total change in entropy? J/K