Question: Pls see image. Consider the function f(x) = (x - 3) 2 defined on the closed interval [1, 4]. Show that there is NO value

Pls see image.

Consider the function f(x) = (x - 3) 2 defined on the closed interval [1, 4]. Show that there is NO value of c in (1, 4) such that f(4) - f(1) = f'(c)(4 - 1). Why does this not contradict to the Mean Value Theorem? Explain your

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