Question: Pls solve it by Python 4. [2] In this question you will approximate the (Gauss) error function erf(x)=2i=0(2i+1)i!(1)ix2i+1=2(x3x3+10x542x7+216x9) Write the code that computes the sum

 Pls solve it by Python 4. [2] In this question you

Pls solve it by Pythonwill approximate the (Gauss) error function erf(x)=2i=0(2i+1)i!(1)ix2i+1=2(x3x3+10x542x7+216x9) Write the code that computes

4. [2] In this question you will approximate the (Gauss) error function erf(x)=2i=0(2i+1)i!(1)ix2i+1=2(x3x3+10x542x7+216x9) Write the code that computes the sum above, and which stops when either of the two events happens: (1) The number of terms added exceeds max_terms. So if max_terms =4, (and option (2) has not stopped the summation), your code should return the sum of the first four terms. (2) The tolerance tol has been reached (and option (1) has not stopped the summation), i.e., the absolute value of the next term to be added is smaller than tol. The remaining parameters and relevant information are given in the template. import math def erf_series (x, tol, max_terms): Approximate the value of erf (x) for x=0.7 to the accuracy tol, given to be 10(10)=1e10 max_terms is defined in print commands in the last two lines in this cell Stop the calculation when either of the two events happens: * the number of terms added exceeds max_steps * the tolerance tol has been reached, i. e., the absolute value of the next term to be added is smaller than tol Return the approximation and text as shown. nn "n \# insert your code here \# note: the output of your print commands does not have to look identical \# to what is shown here, but must give the correct text and the correct value (s) \# note: there could be slight discrepancy in the \# precision of the answer; depending how you code the summation print (erf_series (0.7,1e10,3)) \# should print 0.6798187341903128 (max number of terms reached) print (erf_series (0.7, tol =1e10, max_terms =20)) \# should print 0.6778011938294721 (tolerance reached)

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