plz change to code python

SLLStack: Implementing push (x) (4/4) push (x) u Node (x)O(1) u.next head o( ) head uO(1) if n=0 then 0(1) tail uO(1) nn+1(1) return Module 3 SLLStack pop() pseudo code: (edited) SLLStack: Implementing pop ( ) (4/4) pop()& dato in the head O(1) if n=0 then return nil o(1)x head.x \#temp voviable that stores volue thed head head.next will be vemoved nn14n=1 - if n=0 then tail nil} return x remove() if n=0 then return nil x head. x ff temporary variable storing the value head head.next of head, which we a about to remove. nn1 if n=0 then tail nil return x